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In C, both printf and puts functions are used for printing a string on the console and are defined in stdio.h header file1. However, they have some differences in their usage and behavior.
Here are some of the main differences between printf and puts functions in C:
printf allows us to print formatted strings using format specifiers, such as %d, %s, %f, etc. puts does not support formatting1.
printf does not add a new line character automatically at the end of the output. puts automatically adds a new line character1.
printf returns the number of characters successfully written to the console and a negative value if an error occurs. puts returns a non-negative value on success and EOF (end-of-file) on failure1.
printf can handle multiple strings at one time which helps in concatenating the strings in the output. For example, printf("Hello %s\n", name); prints "Hello" followed by the value of name variable. puts can print a single string at one time1.
printf can print data of different data types, such as integers, floats, characters, etc. puts can print only strings1.
puts can be preferred for printing a simple string because it is generally less costly (implementation of puts is generally simpler than printf), and if the string has formatting characters like ‘%s‘, then printf would give unexpected results. Also, if the string is a user input, then the use of printf might cause security issues2.
If you do not want the cursor to be moved to the next line after printing a string with puts, you can use the following variation of puts: fputs(str, stdout)1.
Learn more✕This summary was generated using AI based on multiple online sources. To view the original source information, use the "Learn more" links. WEBMar 16, 2010 · Learn the difference between printf() and puts() in C, two functions to write strings to stdout. See examples, explanations, and answers from experts and users.
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WEBFeb 16, 2011 · print outputs each argument, followed by $,, to $stdout, followed by $\. It is equivalent to args.join($,) + $\. puts sets both $, and $\ to "\n" and then does the same …
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