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  2. Mathematical Operations and Elementary Functions · The Julia

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    How to divide integers with / function in Julia?TLDR: use ÷. Dividing integers with the / function in Julia returns floating point numbers. Importantly, it promotes integers to floating point numbers before it does the division. For example, the number 10^16-1 is obviously divisible by three:
    What is a mathematical function in Julia?Julia provides a comprehensive collection of mathematical functions and operators. These mathematical operations are defined over as broad a class of numerical values as permit sensible definitions, including integers, floating-point numbers, rationals, and complex numbers, wherever such definitions make sense.
    Does Julia support arbitrary precision integers and floating point numbers?To allow computations with arbitrary-precision integers and floating point numbers, Julia wraps the GNU Multiple Precision Arithmetic Library (GMP) and the GNU MPFR Library, respectively. The BigInt and BigFloat types are available in Julia for arbitrary precision integer and floating point numbers respectively.
    What types of numerical conversion does Julia support?Julia supports three forms of numerical conversion, which differ in their handling of inexact conversions. If T is a floating-point type, the result is the nearest representable value, which could be positive or negative infinity. x % T converts an integer x to a value of integer type T congruent to x modulo 2^n, where n is the number of bits in T.
    How do I compare floats and unsigned integers in Julia?Mixed-type comparisons between signed integers, unsigned integers, and floats can be tricky. A great deal of care has been taken to ensure that Julia does them correctly. For other types, isequal() defaults to calling ==(), so if you want to define equality for your own types then you only need to add a ==() method.
    What arithmetic does Julia use?One thing to consider for this specific case is that Julia provides cld, div, and fld to compute ceil(Int, a/b), round(Int, a/b) and floor(Int, a/b) using only integer arithmetic, which is likely faster and also won't run into rounding issues. you also got ÷ (typed by \div then tab) to do the integer division. Very good to know Oscar and 张实唯 .
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