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Dec 23, 2014 · A seesaw with a mass of 5 kg has one block of mass 10 kg two meters to the left of the fulcrum and another block 0.5 m to the right of the fulcrum. If the seesaw is in equilibrium, A. find the mass of the second block. B. find the force exerted by the fulcrum I have trouble finding the force exerted by the fulcrum; I keep setting up the wrong ...

Lab 13: Torque and Rotational Equilibrium Objectives Determine the mass of the meter stick by the application of known torques to the meter stick. Compare the total clockwise and the total anticlockwise torques when the system is in equilibrium > Determine the mass of an unknown object by using it along with known masses to produce rotational equilibrium. Compare the …

Lab 13: Torque and Rotational Equilibrium Objectives Determine the mass of the meter stick by the application of known torques to the meter stick Compare the total clockwise and the total anticlockwise torques when the system is in equilibrium → Determine the mass of an unknown object by using it along with known masses to produce rotational equilibrium. Compare the …

Feb 24, 2012 · Equilibrium Rotational Translational Feb 24, 2012 #1 sgstudent. 739 3. When a ruler is placed on a pivot ...

Dec 11, 2017 · What I understand is that we want to get the value of RH, which is equal in magnitude to friction. So to do this, we do rotational equilibrium - the total of all the moments must be zero. What I don't understand is why is it set equal to RH times 4? I don't understand this. RH is acting at the end of the latter, which is 5 meters long.

May 18, 2008 · Rotational equilibrium exists when the total net torque on an object is zero. Static equilibrium is when the object is also not in motion. You can apply both concepts to a car (depending on the situation of course). You can definitely calculate the torque on a car. If a car is moving on a circular track at constant speed, what is the net torque ...

Dec 24, 2013 · Imagine joining the two ends with a massless bar of some sort and placing a triangle underneath that massless bar such that the two halves are in translational and rotational equilibrium. Now imagine the COM of each piece and remember that the clockwise torque has to equal the counter clockwise torque to maintain rotational equilibrium.

Question: M25a Prelab: Rotational Equilibrium and Rotational Dynamics Read lab instructions before answering the questions IMPORTANT In M25a experiment, you are going to observe Newton's Second Law for rotational motion, experimentally determine moment of inertia of a platform and of a hollow cylinder ("hoop"), and compare your experimental values with

Report on Laboratory Experiment "Rotational Equilibrium" Part III: Optional experiment. Put an additional clamp and hanger in the stick and hang 50 g and 100 g masses as shown below (Figure 4). Your experimental task is to hang a third mass from the empty hanger and bring the stick to equilibrium.

Answer to LAB REPORT ROTATIONAL EQUILIBRIUM Table 9.1: LAB REPORT ROTATIONAL EQUILIBRIUM Table 9.1: Rotational equilibrium condition-Part I. Equilibrium position of the meter stick: x, = 0.50 m Mass of each hanger = __ X_ kg Total mass (kg) Force (N) F=Mg Torque (N-m) T=Fd M=m+manger Lever arm (m) d= |x - xol d, = .40 M = 0.loo F, = 1,= M = 0.200 F = d₂ = …