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    Upvotes21Top Answeredited May 23, 2017 at 12:40

    Assume the default mask of 0666. umask 0022 would make the new mask 0644 (0666-0022=0644) meaning that group and others have read (no write or execute) permissions.

    The "extra" digit (the first number = 0), specifies that there are no special modes.

    If mode begins with a digit it will be interpreted as octal otherwise its meant to be symbolic.

    0 is ...

    4000 = SUID
    2000 = SGID
    1000 = sticky bit

    The SUID bit, short for set-user-ID, causes an executable program to run with the effective user id (uid) of the owner -- in other words, no matter who executes ...

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    WEBFeb 23, 2021 · To calculate the umask value, simply subtract the desired permissions from the default one: Umask value: 777-750 = 027. The desired umask value represented in numeric notation is 027. To …

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    WEBJul 28, 2022 · Just like the mode bits, the umask value represents the same three sets of permissions---owner, group, and others---and represents them as three Octal digits. You'll sometimes see them written as four …

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    WEBMay 11, 2024 · Use the umask command to set default file permissions on Linux and Unix-like machines. Finding the current shell’s umask value. The umask command without any arguments will display the current value of …

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