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edited Mar 14, 2022 at 14:16You can use a list comprehension with enumerate:
indices = [i for i, x in enumerate(my_list) if x == "whatever"]The iterator enumerate(my_list) yields pairs (index, item) for each item in the list. Using i, x as loop variable target unpacks these pairs into the index i and the list item x. We filter down to all x that match our criterion, and select the indices i of these elements.
Content Under CC-BY-SA license python - How to find all occurrences of an element in a list - Stack ...
WEBMay 6, 2022 · This solution uses np.where and np.unique to find the indices of all unique elements in a list. Using np.where on an array (including the time to convert the list to an array) is slightly slower than a list-comprehension on a list, for finding all indices of all …
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