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- Equidistant examplesEquidistant refers to places or points that are equal in distance from each other12345.Examples of equidistant include135:
- Points on a circle are equidistant from its center.
- Montreal is roughly equidistant from New York, Boston, and Toronto.
- Parallel lines are always equidistant.
- Any point on the perpendicular bisector of a line segment is equidistant from the segment's endpoints.
- The distance between two points can be calculated using the distance formula.
Learn more:✕This summary was generated using AI based on multiple online sources. To view the original source information, use the "Learn more" links.Equidistant examplesPoints on a circle are equidistant from its center. Montreal is roughly equidistant from New York, Boston, and Toronto. Recent Examples on the Web Both are around 1,700-square-foot ranches with similar layouts, located in 20-year old developments equidistant to downtown St. Louis.www.merriam-webster.com/dictionary/equidistantEquidistant examplesThe same distance (from each other, or in relation to other things). Example: parallel lines are always equidistant Another Example: point B is equidistant from points A and C (try moving them around)www.mathsisfun.com/definitions/equidistant.htmlEquidistant examplesPlaces or points that are equidistant have equal distances between them. : Along the avenue, all the trees were of the same height and were equidistant. He checked the other two meters, positioned at equidistant points around the edge of the building. Australia is roughly equidistant from Africa and South America.dictionary.cambridge.org/dictionary/english/equidist…Equidistant examplesEquidistance in geometry
- Parallel lines Parallel lines are equidistant from each other; any point on one line is always equal in distance from the other line.
- Parallel planes Like parallel lines, parallel planes are also equidistant from each other. ...
www.math.net/equidistantEquidistant examplesSolved Examples on Equidistant
- Example 1. Find the distance between the points A (-1, 2) and B (1/2, 5/2) using the distance formula. Solution: Here, x1 x 1 = -1; y1 y 1 = 2; x2 x 2 = 1/2; y2 y 2 = 5/2. ...
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