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edited May 22, 2021 at 13:16Remember that #define performs a textual substitution. You end up with this:
maxi = max(maxi, maxi * long long(a));Which is invalid, since the type name for a functional cast can't, roughly speaking, contain spaces at the top level. So, unsigned int(a), long double(a), etc, are all invalid for this the same reason.
The solution is either to use using instead of #define:
using ll = long long;or to do (ll)a, since in this case the spaces are allowed.
But if I were you, I would get rid of ll and use (long long)a, since ll is a rather non-descriptive nam...
Content Under CC-BY-SA license Using preprocessing directive #define for long long
WEBMay 22, 2021 · There's nothing wrong with #define ll long long (other than the possibility you'll confuse it with 11), it does exactly what it's supposed to do. However, the cast ll(a), which translates to long long(a), is invalid (no spaces allowed in this form). You need to use (ll)a, which becomes (long long)a.
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WEBIf the number is even too big for long the result is implementation-defined (probably just a number of type long int that has been truncated for backward compatibility). In this case you have to explicitly use the LL suffix to enable the long long extension (on most compilers).
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